9/x-9-(18/x^2)

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Solution for 9/x-9-(18/x^2) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

9/x-(18/(x^2))-9 = 0

9/x-18*x^-2-9 = 0

9*x^-1-18*x^-2-9 = 0

t_1 = x^-1

9*t_1^1-18*t_1^2-9 = 0

9*t_1-18*t_1^2-9 = 0

DELTA = 9^2-(-18*(-9)*4)

DELTA = -567

DELTA < 0

x belongs to the empty set

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